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CGP EDU Academic Team
Published on: September 12, 2026
A mass of 0.5kg moving with a speed of 1.5 m/s on a horizontal smooth surface, collides with a nearly weightless spring of force constant $l_k = 50\,N/m$ . The maximum compression of the spring would be
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A
The kinetic energy of mass is converted into potential energy of a spring
$\frac{1}{2}mv^{2} = \frac{1}{2}kx^{2}$ ⇒ ⇒ $x = \sqrt{\frac{mv^{2}}{k}} = \sqrt{\frac{0.5 \times (1.5)^{2}}{50}} = 0.15m$
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